Get file name

I have no idea what you're actually asking - your question doesn't make sense. Can you clarify your question (maybe with an example)?

Regards,

Andrew.

Sorry,I means there are some datebase files(A,B,C,D,...) in a content and I want to write a script to get these file's name(A,B,C,D....),and then get information in these files one by one.

So,how should I do with script?

Thanks a lot!

Hi,

Your question is still not clear.  When you say "content" did you mean "context" ?  If so, you cannot reverse engineer what is encoded in a context file.  In the Cadence supplied context files there is a .toc file alongside that shows which functions are included in the .cxt file.  If you are talking about loading procedures from a .il file, when using the debugger Virtuoso retains information about where a function is defined (which file, which line in that file) - you can get similar information by running the SKILL Surveyor (Tools -> SKILL Development -> Surveyor) and turning on the .defn and .info file generation (where functions are defined and used, respectively) - this statically analyses the files that you setup on the form.

I'm not sure if this helps, but hopefully it does.

Regards,

Lawrence.

Maybe you're asking how to read the files in a directory? We're guessing wildly here...

getDirFiles() would do that though.

Rather than everyone wasting time trying to guess what your question is, please ask a clear and precise question.

Kind Regards,

Andrew.