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Regular Expression: detecting 2 or more consecutive spaces oddity

Sheppy

Hi,

For a particular script I have to check whether or not a string has two or more consecutive spaces between lower-case characters. Zero and one space are allowed, two or more not. I am using rexMatchp() to check. Please have a look at the following code+output:

rexMatchp("[a-z][ ]{2,}[a-z]" "test test")

nil

rexMatchp("[a-z][ ]{2,}[a-z]" "test  test")

nil

rexMatchp("[a-z][ ]{2,}[a-z]" "test   test")

nil

rexMatchp("[a-z][ ][ ]+[a-z]" "test test")

nil

rexMatchp("[a-z][ ][ ]+[a-z]" "test  test")

t

rexMatchp("[a-z][ ][ ]+[a-z]" "test   test")

t

The three last commands do exactly what I want. However, the first three do not work, although this is perfectly legal syntax for a regular expression. I found in the Virtuoso documentation that using {} to specify the number of occurrences is supported, but it clearly doesn't work in my example.

Am I doing something wrong?

With kind regards,

Sjoerd

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