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Running 2 procedures or function in 1 bindkey

GDCRA

Hi,

I was spying on skill command in CIW when I am doing some graphical actions such as clicking netlistcreat form and clicking "Apply" in order to create netlist.

I thought I will able to create keybinding to run this step, so I was trying

hiSetBindKey("Schematics" "<Key>F12" "xcreateNetlist() _hiFormApplyCB(xcreateNetlistForm)")

But its on working. For some reason, it get stucked at 1st stage of opening form. When I close this form, it perform 2nd part of nestling. So its waiting for something between step 1 and step 2.

Can someone help here ?

Thanks

Parents

  • Hi Lawrence,

    <pedantryAlert>

    Whilst I tend to follow the convention you suggest (although generally speaking I write in LISP syntax rather than using operators at all, as you know), strictly speaking the only difference between ~> and -> is when the left-hand-side is a list.

    If the left-hand-side is a singleton object, they are equivalent. If the left-hand-side is a list, then -> treats the list as a disembodied property list; the ~> operator does an implicit "foreach mapcar" across the list - so in other words if you do theList~>prop it will return a list of all the resulting values that you'd get if you did ~>prop for each member of the list.

    </pedantryAlert>

    Regards,

    Andrew.

Reply

  • Hi Lawrence,

    <pedantryAlert>

    Whilst I tend to follow the convention you suggest (although generally speaking I write in LISP syntax rather than using operators at all, as you know), strictly speaking the only difference between ~> and -> is when the left-hand-side is a list.

    If the left-hand-side is a singleton object, they are equivalent. If the left-hand-side is a list, then -> treats the list as a disembodied property list; the ~> operator does an implicit "foreach mapcar" across the list - so in other words if you do theList~>prop it will return a list of all the resulting values that you'd get if you did ~>prop for each member of the list.

    </pedantryAlert>

    Regards,

    Andrew.

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