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Sorting list by sublist elements

climbnc

I have a list like the following

myList =(("I1" 0 0) ("I2" 2 1) ("I3" 1 1))

i would like to sort this list by the 2nd or 3rd element in the sublists.  the results would look like the following sorting by the 2nd element.

(("I1" 0 0) ("I3" 1 1) ("I2" 2 1)

can anyone help with this?  Your help is much appreciated.

Thanks,

Chris                    

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  • Andrew Beckett

    Hi Chris,

    myList=sort(myList lambda((a b) cadr(a)<cadr(b)))

    The lambda creates a temporary (nameless) function with two arguments (the two list items to be compared), and then the body of that function is comparing the 2nd element of each sublist (using the cadr).

    A word of caution: sort is a destructive function (changes the list in place) so make sure you use the return value of the sort function as otherwise slightly odd things can happen.

    Regards,

    Andrew.

  • climbnc
    in reply to Andrew Beckett

    Thank you Andrew for your help.

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  • climbnc
    in reply to Andrew Beckett

    Thank you Andrew for your help.

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