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dbConcatTransform calculation error

NickA

I'm tryinng to compute teh location of a pin which is several levels down in the hierarchy...

Top layout 

    -> Analog instantiated in top with rotation R0 at (0,0)

           -> General instantiated in Analog with R0 at(819.22,136.62)

                  -> Osc instantiated in General with MX rotation at (1811.96,2255.96).

Inside Osc there is a pin at local coords (101.485,1.625). In the top level this appears at (2733.665,2390.955), ie (819.22+1811.96+101.485 , 136.62+2255.96-1.625). However, when I combine the General and Osc coordinates with dbConcatTrasform, it returns the Osc location as 2631.18,2119.34. The x-coord is correct, but the Y is not. It appears to be getting confused by the MX rotation.

I'm using Result = dbConcaatTransform(Arg1 Arg2), with the below values

Arg1: ((819.22 136.62) "R0" 1.0)

Arg2: ((1811.96 2255.96) "MX" 1.0)

Result: ((2631.18 2119.34) "MX" 1.0)

Any idea what I'm doing wrong?

Parents
  • Andrew Beckett

    You have the arguments to the dbConcatTransform the wrong way around. You need to start bottom-up (left to right):

    Result = dbConcaatTransform(Arg2 Arg1)

    ((2631.18 2392.58) "MX" 1.0)

    Then if you do:

    dbTransformPoint(pinLoc Result)

    it outputs:

    (2732.665 2390.955)

    Andrew

Reply
  • Andrew Beckett

    You have the arguments to the dbConcatTransform the wrong way around. You need to start bottom-up (left to right):

    Result = dbConcaatTransform(Arg2 Arg1)

    ((2631.18 2392.58) "MX" 1.0)

    Then if you do:

    dbTransformPoint(pinLoc Result)

    it outputs:

    (2732.665 2390.955)

    Andrew

Children
  • NickA
    in reply to Andrew Beckett

    Yes, that worked. Thanks very much!

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