calculator numconv function

sorry, when ı send my plot to calculator

I think you should use the analog to digital functions that were referenced in the other thread you posted in after this. The numConv is really for single valued text numbers and will convert them into a different number base. I don't think it's the right solution here.

Andrew

OK, so the bus output are analog, not digital - the y-axis is in volts. So the approach you need to take is exactly as I described before - use Measurements->Analog to Digital to convert the analog bits into a digital bus (with your chosen radix). Then you probably want to convert that back into a voltage so that you can perform a PSD on it.

Here's an example of an A2D converter output which has been driven with a sine wave input.

I took the 8 digital bus signals shown at the top, and converted them to a bus using the form like this:

This gave the bus in the middle (below it is the expansion into the individual logic bits). If you zoom in, you'll see the numbers on the bus (note I picked. Unsigned Decimal because that's what my ADC would have produced, but the Radix can be signed Decimal too).

The bottom curve (in both plots) was the result of selecting "mybus" and using Measurements->Digital to Analog and converting it back into an analog waveform. That means you've now got an analog-like signal from your original digital bus (which was in volts rather than logic) and you can then do whatever signal processing you like on that.

Regards,

Andrew.

Sır, why I get 0. U want to say that digital output is not ideal u should convert to bits?

Well, with a centre value of 4, 800mV is always below 4, and so it's always zero. You probably want to enter a centre value of 400m or 0.4.

Andrew

In addition to this, we can create bus from the trace. But ı can not any signal in these section although selecting my signals before click trace-create-bus. It is since analog bits?

abdurrahman0234 said:

In addition to this, we can create bus from the trace. But ı can not any signal in these section although selecting my signals before click trace-create-bus. It is since analog bits?

I have no idea what you mean by this question.

Andrew

I understand sir. But I get no digital signal as in the above pic when convert analog to digital. Why please 

SORRY. I achieved

while converted digital to analog, high and low voltages range is; -4*840m for low and 3*840m for the decimals between  -4 and 3?

(vhi+vlo)/2 this formula is constant?

(vhi+vlo)/2 this formula is constant?

I assume you're referring to the X: (vhi+vlo)/2. That is indicating what voltage would be used if there are any "unknowns" in the digital waveform. There won't be if you use the "Center" mode in the analog to digital (you'll only get X if you have used the High/Low setting on analog to Digital, and the signal stays between the low and the high for longer than a certain time).

Andrew

Sır, dıgıtal bıts are converted to analog bıts, wrongly. For example, digital bit '4' is converted to 226mv and  bit '-1' is converted to 336mv. I dont understand

Why negative decimals dont take a negative voltage

abdurrahman0234 said:

Sır, dıgıtal bıts are converted to analog bıts, wrongly. For example, digital bit '4' is converted to 226mv and  bit '-1' is converted to 336mv. I dont understand

I don't understand either, mainly because you've posted on the end of an old thread (you had this working before, so I presume it's something different) and you've not provided any supporting information - such as a graph of the results, what you entered on the form, and so on. I can't read your mind!

Andrew

when ı converted  digital bits to analog bits, ıt takes decimals wrongly for the voltage output. For example, '-1' digital bit should be 840mv or else '-2' decimal should be at the minumum level but graph show not coorect

analog bıts shows not correct for the digital bits.Hı:3360m li:-840m X=(Xİ + Lİ)/2

OK - when I posted before I'd not seen your picture as you posted three posts rather than combining into one.

It seems that when converting the digital bus back into a single analog waveform, the conversion does not take into account whether you'd marked your bus as being displayed with the radix signed or unsigned. It simply uses the value of the bus as a binary sequence - it seems to always be treated as unsigned. It would seem to be a reasonable enhancement request to allow the conversion to analog to treat the input as a signed bus - so you should contact customer support to request this enhancement.

Goodness me, whilst typing this you've posted 3 more single line responses. You're doing your best to really annoy me so this will be my last answer.

Ok, Sir. I have to look psd of the analog bits. There are any way of  digital bus converting to analog? I think that ıt will not be correct sımulation with wrong analog bits

Now I'm going to go against what I said earlier. You should still contact customer support for this, but it's actually possible to convert the value the way you want. In my case I have an 8 bit unsigned bus, so I converted this to analog with a minimum of 0, and maximum of 255. I then sent this to the calculator:

awvDigital2Analog(awvCreateBus("thebus" list(awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<7>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<6>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<5>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<4>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<3>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<2>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<1>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<0>" ) nil nil 0.4 nil "centre") ) "Signed Decimal") 255 0 "(vhi+vlo)/2" ?mode "busvalue" ?outWaveType "zeroT" ?risetime 0 ?falltime 0)

I added 128 (i.e. half the range of an 8 bit value), and then surrounded the expression with abApplyToTwoWaves('modf expression 256.0) as found in this post. So I got this:

abApplyToTwoWaves('modf awvDigital2Analog(awvCreateBus("thebus" list(awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<7>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<6>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<5>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<4>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<3>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<2>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<1>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<0>" ) nil nil 0.4 nil "centre") ) "Signed Decimal") 255 0 "(vhi+vlo)/2" ?mode "busvalue" ?outWaveType "zeroT" ?risetime 0 ?falltime 0)+128 256.0)

I finally subtracted 128 again, and got this:

abApplyToTwoWaves('modf awvDigital2Analog(awvCreateBus("thebus" list(awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<7>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<6>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<5>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<4>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<3>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<2>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<1>" ) nil nil 0.4 nil "centre") awvAnalog2Digital(leafValue( VT("/data<7:0>") "bit" "/data<0>" ) nil nil 0.4 nil "centre") ) "Signed Decimal") 255 0 "(vhi+vlo)/2" ?mode "busvalue" ?outWaveType "zeroT" ?risetime 0 ?falltime 0)+128 256.0)-128

This gives me:

Note that my vertical markers are showing the bus value (the bus has a signed decimal radix) - and you can see the voltages match. Of course, if your bus widths are different you'll need to change the 128 and 256 in the above expression (note the last argument of abApplyToTwoWaves needs to be a float, so must have .0 at the end).

Of course, this would be much simpler if there was a built-in way to convert the digital to analog treating it as a signed number in the first place (but that needs an enhancement). You could also write a Verilog-A DAC model which does the same thing.

Andrew