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"list of uint(bits:8)" versus "list of byte"

I need some help to understand few implementation aspects, like "list of uint(bits:8)" is equivalent to "list of byte". Using which one is better/advantageous (with respect to simualtion performance, etc., )?

In other words, is using "list of uint(bits:8)" advantageous over "list of byte" ?

StephenH over 14 years ago

So far as I recall, it doesn't matter. The only performance problem comes if you make the uint bigger than the number of bits in the CPU architecture, as that impacts the way the data gets stored.
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kgss over 14 years ago

Thanks for the response, Stephen.
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Ravisinha over 14 years ago

I think its related with the signed and unsigned number also... If it is list of byte then it is a signed no.. (-127 to +127) and if it is a list of uint(bits:8) then its a unsigned no... (-256 to +256).
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