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printing struct members:

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Hello, i've got a struct with planty of data members, and some methods. i'd like to be able to print all members automatically (without specify each one in particular). i.e. struct X{ A:uint; B:string; C:bool; D:uint; ... }; the function 'print X' will produce: " A = ... B = ... ... " thanks,


Originally posted in cdnusers.org by zcabeli11

  • Hi,

    you can use the built-in print function:

    Specman s> print sys.s
    sys.s = s-@0: s of unit: sys
    ---------------------------------------------- @s
    0 a: 1840385568
    1 b: FALSE
    2 c: 1554590122
    3 d: ""

    from within your code you can use "print me;".

    Nils


    Originally posted in cdnusers.org by nls

  • Hi....... You can print struct field by taking instance of that struct and printing using "print" statement. e.g. struct X{ A:uint; B:string; C:bool; D:uint; ... }; // Take instance of this struct y : x; print y;


    Originally posted in cdnusers.org by vlsi_dude

  • You can also use the built in print command in conjunction with "message" which makes it more efficient.
    This way the verbosity settings will also affect the printing.

    For example :

    messagef(LOW,"new packet just added \n") { print new_packet };




    Yaron


    Originally posted in cdnusers.org by thinkverification

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