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About ports

analogy

Lets say that you have a two port network.If the output port isn't matched to 50 Ohms, is it still safe to use output port resistance as 50 Ohms and get ZM2 ?


Secondly , if the output isn't matched, what should be the port resistance ?

Thanks.

Parents

  • Ok.And how about compression point ?

    So this is what happened - for a given circuit, when my output port resistance was 50 Ohms, my compression point was ~ -47dBm while as I changed output port resistance to 4K Ohms (my output impedance was ~ ) , compression point was ~ -13dBm for 50 Ohms.


    Strangely, output port resistance affects compression point.This means that somehow output port resistance affects the overall output resistance of that given circuit.


    Does it make sense ? Do I need to match my output to 50 Ohms, given that my port resistance is 50 Ohms ?

    Thanks.

Reply

  • Ok.And how about compression point ?

    So this is what happened - for a given circuit, when my output port resistance was 50 Ohms, my compression point was ~ -47dBm while as I changed output port resistance to 4K Ohms (my output impedance was ~ ) , compression point was ~ -13dBm for 50 Ohms.


    Strangely, output port resistance affects compression point.This means that somehow output port resistance affects the overall output resistance of that given circuit.


    Does it make sense ? Do I need to match my output to 50 Ohms, given that my port resistance is 50 Ohms ?

    Thanks.

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