Getting the BBox of a rotated component

 The bBox is the orthogonal extents covered by the symbol and is generally not of much use except as a test if the symbol will fit into the board extents or as a quickout test for DRC code. The bBox contains everything in the symbol, so if you build a symbol with notes, dimensioning, etc. its bBox will be much larger then what is required for placement work. Typically, you want to use items like PLACE_BOUNDS or keepouts which are shapes present off the "children" link of the symbol.

 If you really want the un-rotated extents of the a symbol, you can consider using the bBox of the symbol def which is:

      symbol->definition->bBox

You will need to correct this bBox for the origin of the symbol instance (e.g add symbol->xy to the def's bBox coords). Also the symbol def's bBox will not take into account any symbol instance edits (this is atypical).

Finally you can always use axlGeoRotatePt on each xy of the bBox which will do the math. But you must send it both negative angle and an un-mirror for the correct result.

Yes, I understood about the extents issues but left them off the post for succinctness.  However, your reference to "axlGeoRotatePt" is what I was missing... and that's what will provide what I'm after!!  THANKS!! 

;First, get the points of the bounding box
p1 = car(object->bBox)
p2 = cadr(object->bBox)
p3 = list(car(p1) cadr(p2))
p4 = list(car(p2) cadr(p1))
pnts = list(p1 p2 p3 p4)

;Second, find center of bounding box
cntr_x = (axlDistance(p1 p4)/2) + min(car(p1) car(p4))
;((car(p1) - car(p2))/2) + car(p1)
cntr_y = (axlDistance(p1 p3)/2) + min(cadr(p1) cadr(p3))
;((cadr(p1) - cadr(p2))/2) + cadr(p1)
cntr_xy = list(cntr_x cntr_y)

;Third, compute the rotated points
r_pnts = nil
foreach(pnt pnts r_pnts = cons(axlGeoRotatePt(object->rotation pnt cntr_xy) r_pnts))

;List of the points
foreach(r_pnt r_pnts println(r_pnt))

Randy -  Nice snippet!!  Thanks!!!  This will be helpful!