Stats

Replies 4
Subscribers 159
Views 13748
Members are here 0

Getting the BBox of a rotated component

Does anyone have a method for getting the absolute coordinates for the vertices of a rotated component/symbol? If you query the DBID itself, you can get the BBox and the rotation. E.g.

componentDBID->symbol->bBox AND componentDBID->symbol->rotation

However, the vertices reported in the BBox are the extents of the symbol with a 0 degree rotation. It seems the only way to get the absolute coordinates for the vertices of the component in its rotated position, you'd need to do some trigonometry. Anyone out there with a better way or perhaps... a code snippet to do the calculations?

THANKS MUCH!!!!

Parents

LSIpkgCad over 16 years ago

Yes, I understood about the extents issues but left them off the post for succinctness. However, your reference to "axlGeoRotatePt" is what I was missing... and that's what will provide what I'm after!! THANKS!!
Cancel
Vote Up 0 Vote Down

Sign in to reply

Cancel

Reply

LSIpkgCad over 16 years ago

Yes, I understood about the extents issues but left them off the post for succinctness. However, your reference to "axlGeoRotatePt" is what I was missing... and that's what will provide what I'm after!! THANKS!!
Cancel
Vote Up 0 Vote Down

Sign in to reply

Cancel

Children

No Data

Cadence Guidelines

Community Guidelines

The Cadence Design Communities support Cadence users and technologists interacting to exchange ideas, news, technical information, and best practices to solve problems and get the most from Cadence technology. The community is open to everyone, and to provide the most value, we require participants to follow our Community Guidelines that facilitate a quality exchange of ideas and information. By accessing, contributing, using or downloading any materials from the site, you agree to be bound by the full Community Guidelines.