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  3. Comparing divided flonum

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Comparing divided flonum

nosaj
nosaj over 14 years ago
 I have a line of code that compares x/zto int(x/z)  :

if( x/z!= int(x/z) then

   printf("not equal\n")

else

  print("equal\n")

)

when x= 0.15 and z= 0.5, it prints not equal because

0.15/0.05 = 3.0

int(0.15/0.05) = 2

But in reality it's equal, how may I correct this in SKILL?

Thanks

 

 

 

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  • nosaj
    nosaj over 14 years ago

    Thanks Lawrence.  

    abs( (x/z) - int(x/z) ) < 1e-6 

    If x = 0.15 and z = 0.05

    abs( (0.15/0.05 ) - int(0.15/0.05) ) < 1e-6

    won't work since int(0.15/0.05) returns 2.0 instead of 3.0. 

    How may I correct this so that I can check if x is an exact multiplier of z?

    Thanks

     

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  • nosaj
    nosaj over 14 years ago

    Thanks Lawrence.  

    abs( (x/z) - int(x/z) ) < 1e-6 

    If x = 0.15 and z = 0.05

    abs( (0.15/0.05 ) - int(0.15/0.05) ) < 1e-6

    won't work since int(0.15/0.05) returns 2.0 instead of 3.0. 

    How may I correct this so that I can check if x is an exact multiplier of z?

    Thanks

     

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