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What is the phase relation between Spectre PSS one period waveform and the corresponding PAC analysis

Dear All,

We use PSS and PAC simulation. But I am still not sure what is the phase relation between Spectre PSS one period waveform and the corresponding PAC sideband's phase.

For example, Let's say PAC Sideband=0 atfrequency=0 has a phase of 40 degree.

Now this phase is referenced to what ? I assume it is related to one period waveform obtained through PSS-time plot .

Could anybody clarify on this. I have used Shooting method for PSS/PAC analysis.

Kind Regards,

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Andrew Beckett over 2 years ago

With PAC analysis, the phase is related to the phase of the source with PAC Magnitude set (there's the PAC Phase parameter on vsource/isource/port which allows you to set it to something other than 0).

Andrew
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Andrew Beckett over 2 years ago

With PAC analysis, the phase is related to the phase of the source with PAC Magnitude set (there's the PAC Phase parameter on vsource/isource/port which allows you to set it to something other than 0).

Andrew
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RFStuff over 2 years ago in reply to Andrew Beckett

Dear Andrew,

Thanks a lot for your reply.

In PAC we find the sideband transfer functions Hm(jw). From these we can find the time-varying periodic transfer function H(jw,t) with period T. T=1/fs, i.e.the period of the LPTV system (the periodic clock that drives the LPTV system). wc=2*pi/T

If I derive let's say H(0,t) from the pac sideband trnasferfunctions at f=0, Hm(0) (m here -50 to +50), how its phase will be with respect to the clock of the LPTV system (as both H(0,t) and the clock are periodic) ?

Below, is the information taken from the publication "Impulse Sensitivity Function Analysis of Periodic Circuits".
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