dbLayerTile need help

You probably could use 'leChopShape', if you are not going to use it within a PCell.

leChopShape( d_shapeId l_points g_closed [ g_remove ] [ x_sides ] )
     => l_newShapes | nil


Cuts the shape d_shapeId using the chop shape l_points.

Thanks Bernd for the quick reply.

Yes you were right, this is exactly what i have done in my code. Now I have already discarded to used dbLayerTile in my code, instead I made a sub routine that fractures a target dbobj both horizontal and vertical using leChopShape. now my code looks much simplier.

by the way, we are both from unterhaching, I'm from fasanenpark.

 Is there any comamnd in skill which splits a polygon into max of 2 rectangles.

I am writing a skill code which needs stretch  all the poly gates by fixed distance and hence entire layout should move accordingly maintaining others shapes like contacts lengts/widths as constant..can anyone help me of how to  go with this?

 Thanks & Regards,

prani

What's wrong with dbLayerTile? Obviously if the polygon is not rectangular or L-shaped, it can't be fractured into only two rectangles, but apart from that, surely that does what you want?

Regards,

Andrew.

 Andrew,

In few cases, poly is getting fractured into more than two rectangles and all the polys(specially polys of "polygon" lpp) are not getting stretched by same length(say 0.015),I dont know how to overcome this and make my code work properly.

 It's not that clear to me why you need to fracture it or precisely what you're trying to do - maybe some pictures would help (you can upload a picture via the "Options" tab at the top). 

Alternatively there are various easily found algorithms for fracturing or decomposing a polygon into rectangles - do a google search for "algorithm to tile polygon with rectangles". However, this is almost certainly overkill if it's an L-shaped polygon - you should be able to detect that reasonably easily and split it yourself. Off the top of my head, without thinking about it enough to be sure that this is correct, I'd say you could do something like this:

1. Ensure that the polygon has 6 points and all angles are 90 degrees (i.e. each successive point only changes the x or y but not both from the last point)
2. Find the bBox of the polygon (the database will return this for you via ~>bBox, but it's easy to compute)
3. Look for a point that is not on one of the four corners of the bounding box, and then that's the point at which you chop the polygon into two (extend the line from the point you've found in the direction of the next point which is not on the bBox corners). That next point will also give you the start of the second rectangle.

This is all relatively straightforward to solve.

Regards,

Andrew.

Andrew,

Finally,I am writing a skill code which increases poly length by 0.015 for the picture attached.

I used

polys=setof(sh cv~>shapes sh~>lpp==list("poly" "drawing"))

dblayerTile(cv "active"  polys)

but all the polys are getting increased by 0.015,in few cases there is an increase of 0.01(which is double)

so,I dont know how to go about it. 

Wouldn't it be easier to find the bBox of all the poly, widen that bBox a bit, use dbLayerSize to increase the size of the poly by a certain amount and then And it with the enlarged bBox (to chop off any oversizing at the top and bottom)?

Something like that?

Andrew.

 And using dbLayerAnd?..ilooks like dbLAyerAnd ts not working out/expected result..

dbLayerAnd should work fine - that was what I meant by "And".

Andrew.